108=3x^2-4x

Solution for 108=3x^2-4x equation:

108=3x^2-4x

We move all terms to the left:

108-(3x^2-4x)=0

We get rid of parentheses

-3x^2+4x+108=0

a = -3; b = 4; c = +108;
Δ = b2-4ac
Δ = 42-4·(-3)·108
Δ = 1312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1312}=\sqrt{16*82}=\sqrt{16}*\sqrt{82}=4\sqrt{82}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{82}}{2*-3}=\frac{-4-4\sqrt{82}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{82}}{2*-3}=\frac{-4+4\sqrt{82}}{-6}
$